本文共 1471 字，大约阅读时间需要 4 分钟。

要解决这个问题，我们需要读取n名学生的姓名、学号和成绩，然后分别输出成绩最高和最低的学生的姓名和学号。以下是详细的解决方案：

方法思路

解决代码

#include 
   
    #include 
    
     #include 
     
      using namespace std;int main() {    int n;    cin >> n;    vector
      
        names(n);    vector
       
         nums(n);    vector
        
          scores(n); for (int i = 0; i < n; ++i) { string line; getline(cin, line); size_t first_space = line.find(' '); size_t second_space = line.find(' ', first_space + 1); string name = line.substr(0, first_space); string num = line.substr(first_space + 1, second_space - first_space - 1); string score_str = line.substr(second_space + 1); int score = stoi(score_str); names[i] = name; nums[i] = num; scores[i] = score; } int max_score = scores[0]; int min_score = scores[0]; int max_index = 0; int min_index = 0; for (int i = 1; i < n; ++i) { if (scores[i] > max_score) { max_score = scores[i]; max_index = i; } if (scores[i] < min_score) { min_score = scores[i]; min_index = i; } } cout << names[max_index] << ' ' << nums[max_index] << endl; cout << names[min_index] << ' ' << nums[min_index] << endl; return 0;}
        
       
      
     
    
   

代码解释

这种方法高效且直接，能够处理所有符合题目要求的输入情况。

转载地址：http://fceiz.baihongyu.com/